Given a string, remove all chars from the string that are present in say another string called filter

solution 1: advantage is that we do not duplicate the string
k = 0
while s[i] <> 0
        found = 0
        for j = 0 ; j < sFilter ; j++
                if s[i] == filter[j]
                        found = 1
                        break
        if ! found
                s[k++] = s[i]
        i++
s[k] = 0